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Question
Let A = `[[2,4],[3,2]]`, `B=[[1,3],[-2,5]]`and `c =[[-2,5],[3,4]]`.Find each of the following: 3A − 2B + 3C
Solution
`3A-2B+3C`
⇒ 3A−2B+3C=3 `[[2 4],[3 2]]-2[[1 3],[-2 5]]+3[[-2 5],[3 4]]`
⇒ 3A−2B+3C=`[[6 12],[9 6]]-[[2 6],[-4 10]]+[[-6 15],[9 12]]`
⇒ 3A−2B+3C=`[[6-2-6 12-6+15],[9+4+9 6-10+12]]`
⇒ 3A−2B+3C=`[[-2 21],[22 8]]`
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