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Question
Solve the following equation:
`3^(x-1)xx5^(2y-3)=225`
Solution
`3^(x-1)xx5^(2y-3)=225`
`rArr3^(x-1)xx5^(2y-3)=3xx3xx5xx5`
`rArr3^(x-1)xx5^(2y-3)=3^2xx5^2`
⇒ x - 1 = 2 and 2y - 3 = 2
⇒ x = 2 + 1 and 2y = 2 + 3
⇒ x = 3 and 2y = 5
⇒ x = 3 and y = 5/2
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