English

The ages of two friends Ani and Biju differ by 3 years. Ani’s father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The ages of Cathy and Dharam differ by 30 years. Find the ages of Ani and Biju - Mathematics

Advertisements
Advertisements

Question

The ages of two friends Ani and Biju differ by 3 years. Ani’s father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The ages of Cathy and Dharam differ by 30 years. Find the ages of Ani and Biju

Solution

The difference between the ages of Biju and Ani is 3 years. Either Biju is 3 years older than Ani or Ani is 3 years older than Biju. However, it is obvious that in both cases, Ani’s father’s age will be 30 years more than that of Cathy’s age.

Let the age of Ani and Biju be x and y years respectively.

Therefore, age of Ani’s father, Dharam = 2 × x = 2x years

And age of Biju’s sister Cathy = `y/2` year

By using the information given in the question,

Case (I) When Ani is older than Biju by 3 years,

x − y = 3 (i)

`2x -y/2 = 30`

4x − y = 60 (ii)

Subtracting (i) from (ii), we obtain

3x = 60 − 3 = 57

`x = 57/3 =19`

Therefore, age of Ani = 19 years And age of Biju = 19 − 3 = 16 years

Case (II) When Biju is older than Ani,

y − x = 3 (i)

`2x - y/2 = 30`

4x − y = 60 (ii)

Adding (i) and (ii), we obtain

3x = 63

x = 21

Therefore, age of Ani = 21 years And age of Biju = 21 + 3 = 24 years

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Pair of Linear Equations in Two Variables - Exercise 3.7 [Page 68]

APPEARS IN

NCERT Mathematics [English] Class 10
Chapter 3 Pair of Linear Equations in Two Variables
Exercise 3.7 | Q 1 | Page 68

RELATED QUESTIONS

Solve `\frac { 2 }{ x } + \frac { 1 }{ 3y } = \frac { 1}{ 5 }; \frac { 3 }{ x } + \frac { 2 }{ 3y } = 2` and also find ‘a’ for which y = ax – 2


Formulate the following problems as a pair of equations, and hence find their solutions:

Ritu can row downstream 20 km in 2 hours, and upstream 4 km in 2 hours. Find her speed of rowing in still water and the speed of the current


Solve the following pair of linear equations

ax + by = c

bx + ay = 1 + c


In Fig. 1, ABCD is a rectangle. Find the value of x and y.


A number consist of two digits whose sum is five. When the digits are reversed, the number becomes greater by nine. Find the number.


The sum of two numbers is 1000 and the difference between their squares is 256000. Find the numbers.


A two-digit number is 4 times the sum of its digits and twice the product of the digits. Find the number.


Let the numerator and denominator of the fraction be x and y respectively. Then the fraction is `x/y`

If the numerator is multiplied by 2 and the denominator is reduced by 5, the fraction becomes `6/5`. Thus, we have

`(2x)/(y-5)=6/5`

`⇒ 10x=6(y-5)`

`⇒ 10x=6y-30`

`⇒ 10x-6y+30 =0`

`⇒ 2(5x-3y+15)=0`

`⇒ 5x - 3y+15=0`

If the denominator is doubled and the numerator is increased by 8, the fraction becomes `2/5`. Thus, we have

`(x+8)/(2y)=2/5`

`⇒ 5(x+8)=4y`

`⇒ 5x+40=4y`

`⇒ 5x-4y+40=0`

So, we have two equations

`5x-3y+15=0`

`5x-4y+40=0`

Here x and y are unknowns. We have to solve the above equations for x and y.

By using cross-multiplication, we have

`x/((-3)xx40-(-4)xx15)=-y/(5xx40-5xx15)=1/(5xx(-4)-5xx(-3))`

`⇒ x/(-120+60)=(-y)/(200-75)=1/(-20+15)`

`⇒x/(-60)=-y/125``=1/-5`

`⇒ x= 60/5,y=125/5`

`⇒ x=12,y=25`
Hence, the fraction is `12/25`


The sum of the numerator and denominator of a fraction is 3 less than twice the denominator. If the numerator and denominator are decreased by 1, the numerator becomes half the denominator. Determine the fraction.


Ten years later, A will be twice as old as B and five years ago, A was three times as old as B. What are the present ages of A and B?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×