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Question
The foot of a ladder is 6 m away from a wall and its top reaches a window 8 m above the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its tip reach?
Solution
Let, length of ladder be AD = BE = `l` m
In ΔACD, by Pythagoras theorem
AD2 = AC2 + CD2
⇒ `l`2 = 82 + 62 .....(i)
In ΔBCE, by pythagoras theorem
BE2 = BC2 + CE2
⇒ `l`2 = BC2 + 82 .......(ii)
Compare (i) and (ii)
BC2 + 82 = 82 + 62
⇒ BC2 = 62
⇒ BC = 6m
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