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Question
The marks of 200 students in a test is given below :
Marks% | 10-19 | 20-29 | 30-39 | 40-49 | 50-59 | 60-69 | 70-79 | 80-89 |
No. of Students | 7 | 11 | 20 | 46 | 57 | 37 | 15 | 7 |
Draw an ogive and find
(i) the median
(ii) the number of students who scored more than 35% marks
Solution
We construct cumulative frequency table of the given distribution :
Marks | No.of students (f) | Cumulative Frequency |
9.5-19.5 | 7 | 7 |
19.5-29.5 | 11 | 18 |
29.5-39.5 | 20 | 38 |
39.5-49.5 | 46 | 84 |
49.5-59.5 | 57 | 141 |
59.5-69.5 | 37 | 178 |
69.5-79.5 | 15 | 193 |
79.5-89.5 | 7 | 200 |
Take a graph paper and draw both the axes.
On the x -axis , take a scale of 1cm=10 to represent the marks.
On the y - axis , take a scale of 1 cm =50 to represent the no. of students .
Now, plot the points (19.5,7) ,(29.5,18) ,(39.5,38) ,( 49.5,84) ,(59.5,141) ,(69.5,178) ,(79.5,193) ,(89.5,200).
Join them by a smooth curve to get the ogive.
(i) No. of terms = 200
.·. Median= `(100 + 101)/2` = 100.5th term
Through mark of 100.5 on y-axis draw a line parallel to x-axis which meets the curve at A. From A, draw a perpendicular to x-axis which meets it at B.
The value of B is the median which is 52.
(ii) From marks % = 35 draw a line parallel to y-axis and meet the curve at R. From R, Draw a perpendicular on y-axis which meets it at S. The difference of the value obtained when subtracted from 200 gives the number of students who scored more than 35%.
⇒ 200 - 23 = 172
172 students scored more than 35 %
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The marks of 200 students in a test were recorded as follows:
Marks % |
0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 | 90-100 |
No. of students |
5 | 7 | 11 | 20 | 40 | 52 | 36 | 15 | 9 | 5 |
Using graph sheet draw ogive for the given data and use it to find the,
- median,
- number of students who obtained more than 65% marks
- number of students who did not pass, if the pass percentage was 35.