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Question
The rate constant for a first order reaction is 60 s−1. How much time will it take to reduce the initial concentration of the reactant to its `1/16`th value?
Solution
t = `2.303/"k" log "a"/("a" - "x")`,
if a = 1 then (a − x) = `1/16`
k = `2.303/60 log 1/(1/16)`
= 0.0462 s−1
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