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The Ratio of Passed and Failed Students in an Examination Was 3 : 1. Had 30 Less Appeared and 10 Less Failed, the Ratio of Passes to Failures Would Have Been 13 : 4. Find the Number - Mathematics

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Question

The ratio of passed and failed students in an examination was 3 : 1. Had 30 less appeared and 10 less failed, the ratio of passes to failures would have been 13 : 4. Find the number of students who appeared for the examination.

Sum

Solution

Let the number of passed students be x and the number of failed students be y.
According to the question,
`x/y = (3)/(1)`
⇒ x = 3y         ....(i)
Now, if 30 less appeared and 10 less failed, then we have
Number of students appeared = x + y - 30
number of failed students = y - 10
∴ number of passed students = x - 20
⇒ `(x - 20)/(y - 10) = (13)/(4)`
⇒  4x - 80 = 13y - 130
⇒  4x - 13y = -50
⇒  4(3y) - 13y = -50         ...[From (i)]
⇒  12y - 13y = -50
⇒  -y = -50
⇒  y = 50
⇒  x = 3 x 50 = 150
⇒  x + y 
= 150 + 50
= 200
Hence, 200 students appeared for the examination.

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Methods of Solving Simultaneous Linear Equations by Elimination Method
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Chapter 8: Simultaneous Linear Equations - Exercise 8.3

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 8 Simultaneous Linear Equations
Exercise 8.3 | Q 19

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