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The Tops of Two Towers of Height X and Y, Standing on Level Ground, Subtend Angles of 30º and 60º Respectively at the Centre of the Line Joining Their Feet, Then Find X : Y. - Mathematics

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Question

The tops of two towers of height x and y, standing on level ground, subtend angles of 30º and 60º respectively at the centre of the line joining their feet, then find x : y.        

Sum

Solution


Let AB and CD be the two towers and E be the mid-point of AC.
Height of the tower, AB = y
Height of the tower, CD = 

it is given that, ∠ AEB=60° and ∠ CED=30°

Also, `AE=EC`

In right Δ AEB, 

`tan 60°= (AB)/(AE)`

⇒ `sqrt3=y/(AE)` 

`⇒ AE=y/sqrt3`

In right ∆CED, 

`tan 60° = (AB)/(AF)` 

⇒ `1/sqrt3=x/(CE)`

`⇒CE=sqrt3x` 

`y/sqrtx=sqrt3x`

`⇒ y=3x`

`⇒x/y=1/3`

`∴ x: y=1:3`

Hence, the ratio of y is 1 : 3. 

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Chapter 12: Trigonometry - Exercise 12.2 [Page 41]

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RD Sharma Mathematics [English] Class 10
Chapter 12 Trigonometry
Exercise 12.2 | Q 7 | Page 41

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