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Question
The value of arg (x) when x < 0 is ______.
Options
0
`pi/2`
π
None of these
Solution
The value of arg (x) when x < 0 is π.
Explanation:
Let z = –x + 0i and x < 0
∴ |z| = `sqrt((-1)^2 + (0)^2)` = 1, x < 0
Since, the point (–x, 0) lies on the negative side of the real axis. ....`(because x < 0)`
∴ Principal argument (z) = π.
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