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Two Charged Particles, with Equal Charges of 2.0 × 10−5 C, Are Brought from Infinity to Within a Separation of 10 Cm. Find the Increase in the Electric Potential Energy During the Process - Physics

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Question

Two charged particles, with equal charges of 2.0 × 10−5 C, are brought from infinity to within a separation of 10 cm. Find the increase in the electric potential energy during the process 

Short Note

Solution

Magnitude of charges, q1 = q2 = 2 × 10−5 C
Initial potential energy = 0
Each is brought from infinity to within a separation of 10 cm.
That is, r = 10 × 10−2
So, increase in potential energy = final potential energy − initial potential energy.
That is, increase in potential energy,

\[∆ \text{U} = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r}\]

\[∆ \text{U} = 9 \times {10}^9 \times \frac{2 \times {10}^{- 5} \times 2 \times {10}^{- 5}}{10 \times {10}^{- 2}} = 36\] J
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Chapter 7: Electric Field and Potential - Exercises [Page 123]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 7 Electric Field and Potential
Exercises | Q 61 | Page 123

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