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A Man Standing on the Deck of a Ship, Which is 8 M Above Water Level. He Observes the Angle of Elevation of the Top of a Hill as 60° and the Angle of Depression of the Base of the Hill as 30°. Calculate the Distance of the Hill from the Ship and the Height of the Hill. - Mathematics

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प्रश्न

A man standing on the deck of a ship, which is 8 m above water level. He observes the angle of elevation of the top of a hill as 60° and the angle of depression of the base of the hill as 30°. Calculate the distance of the hill from the ship and the height of the hill.

उत्तर

Let be the height of hill CE and a man is standing on a ship at the height of 8meter above from the water level.

Let AB = 8, BC = xAD = BC, AB = DCDE = h

∠ACB = 30° and ∠DAE = 60°

We have to find x and H

The corresponding figure is as follows

In ΔABC

`=> tan 30 = 8/x`

`=> 1/sqrt3 = 8/x`

`=> x = 8sqrt3`

Again in  Δ DAE,

`=> tan 60^@ = h/x`

`=> sqrt3 = h/x`

`=> h = xsqrt3`

`=> h = 24`

Therefore H = h + 8`

`=> H = 24 + 8`

=> H = 32

Hence the required distance is `8sqrt3`m and height is 32 m

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अध्याय 12: Trigonometry - Exercise 12.1 [पृष्ठ ३२]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 12 Trigonometry
Exercise 12.1 | Q 42 | पृष्ठ ३२

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