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A Pair of Dice is Thrown. Find the Probability of Getting the Sum 8 Or More, If 4 Appears on the First Die. - Mathematics

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प्रश्न

A pair of dice is thrown. Find the probability of getting the sum 8 or more, if 4 appears on the first die.

उत्तर

Consider the given events.
A = 4 appears on first die
B = The sum of the numbers on two dice is 8 or more.

Clearly,
= {(4, 1), (4, 2), (4, 3), (4, 4) (4, 5), (4, 6)}
n(A) = 6

B = {(2, 6), (3, 5), (3, 6), (4, 4), (4, 5), (4, 6),(5, 3), (5, 4), (5, 5) (5, 6), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
n(B) = 15

\[\text{ Now } , \]

\[A \cap B = \left\{ \left( 4, 4 \right), \left( 4, 5 \right), \left( 4, 6 \right) \right\}\]

\[ \therefore \text{ Required probability } = P\left( B/A \right) = \frac{n\left( A \cap B \right)}{n\left( A \right)} = \frac{3}{6} = \frac{1}{2}\]

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Probability Examples and Solutions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 31: Probability - Exercise 31.3 [पृष्ठ ३५]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 31 Probability
Exercise 31.3 | Q 17 | पृष्ठ ३५

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