Advertisements
Advertisements
प्रश्न
A vertical stick 20 m long casts a shadow 10 m long on the ground. At the same time, a tower casts a shadow 50 m long on the ground. The height of the tower is
विकल्प
100 m
120 m
25 m
200 m
उत्तर
Given: Vertical stick 20m long casts a shadow 10m long on the ground. At the same time a tower casts the shadow 50 m long on the ground.
To determine: Height of the tower
Let AB be the vertical stick and AC be its shadow. Also, let DE be the vertical tower and DF be its shadow.
Join BC and EF.
In ΔABC and ΔDEF, we have
`∠A=∠D=90^o`
`∠C=∠F`
`Δ ABC ∼ Δ DEF`
We know that in any two similar triangles, the corresponding sides are proportional. Hence,
`(AB)/(DE)=(AC)/(DF)`
`20/(DE)=10/50`
`DE=100m`
Hence the correct answer is option `a`.
APPEARS IN
संबंधित प्रश्न
D and E are points on the sides AB and AC respectively of a ΔABC such that DE║BC
If AD = 3.6cm, AB = 10cm and AE = 4.5cm, find EC and AC.
In each of the following figures, you find who triangles. Indicate whether the triangles are similar. Give reasons in support of your answer.
In ∆ABC, the bisector of ∠A intersects BC in D. If AB = 18 cm, AC = 15 cm and BC = 22 cm, find BD.
In a triangle ABC, N is a point on AC such that BN ⊥ AC. If BN2 = AN . NC, prove that ∠B = 90°.
The areas of two similar triangles are 169 cm2 and 121 cm2 respectively. If the longest side of the larger triangle is 26 cm, what is the length of the longest side of the smaller triangle?
If ∆ABC and ∆DEF are similar such that 2AB = DE and BC = 8 cm, then EF =
If ABC and DEF are similar triangles such that ∠A = 47° and ∠E = 83°, then ∠C =
ABCD is a trapezium such that BC || AD and AD = 4 cm. If the diagonals AC and BD intersect at O such that \[\frac{AO}{OC} = \frac{DO}{OB} = \frac{1}{2}\], then BC =
In the given figure, if ∠ADE = ∠ABC, then CE =
In an isosceles triangle ABC if AC = BC and AB2 = 2AC2, then ∠C =
