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प्रश्न
AB and CD are two equal chords of a drde intersecting at Pas shown in fig. P is joined to O , the centre of the cirde. Prove that OP bisects ∠ CPB.
उत्तर
Draw perpendiculars OR and OS to CD and AB respectively.
In triangle ORP and triangle OSP
OP= OP
OR = OS (Distance of equal chords from centre are equal)
∠ PRO = ∠ PSO (right angles)
Therefore, Δ ORP ≅ Δ OSP
Hence, ∠ RPO = ∠ SPO
Thus OP bisects ∠ CPB.
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संबंधित प्रश्न
n Fig. 2, PQ and PR are two tangents to a circle with centre O. If ∠QPR = 46°, then ∠QOR equals:
(A) 67°
(B) 134°
(C) 44°
(D) 46°
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