Advertisements
Advertisements
प्रश्न
Calculate the standard deviation for the following data:
Class: | 0-30 | 30-60 | 60-90 | 90-120 | 120-150 | 150-180 | 180-210 |
Frequency: | 9 | 17 | 43 | 82 | 81 | 44 | 24 |
उत्तर
Class |
\[f_i\]
|
Midpoint
\[\left( x_i \right)\]
|
\[y_i = \frac{x_i - 105}{30}\]
|
\[{y_i}^2\]
|
\[f_i y_i\]
|
\[f_i {y_i}^2\]
|
0−30 | 9 | 15 | −3 | 9 | −27 | 81 |
30−60 | 17 | 45 | −2 | 4 | −34 | 68 |
60−90 | 43 | 75 | −1 | 1 | −43 | 43 |
90−120 | 82 | 105 | 0 | 0 | 0 | 0 |
120−150 | 81 | 135 | 1 | 1 | 81 | 81 |
150−180 | 44 | 165 | 2 | 4 | 88 | 176 |
180−210 | 24 | 195 | 3 | 9 | 72 | 216 |
\[\sum f_i = N = 300\]
|
\[\sum f_i y_i = 137\]
|
\[\sum f_i {y_i}^2 = 665\]
|
Mean,
\[\sigma^2 = \frac{h^2}{N^2}\left[ N\sum f_i {y_i}^2 - \left( \sum f_i y_i \right)^2 \right]\]
\[ = \frac{900}{90000}\left[ 300 \times 665 - 18769 \right]\]
\[ = \frac{1}{100}\left[ 199500 - 18769 \right]\]
\[ = \frac{180731}{100} = 1807 . 31\]
\[SD, \sigma = \sqrt{1807 . 31} = 42 . 51\]
APPEARS IN
संबंधित प्रश्न
Find the mean and variance for the first n natural numbers.
Find the mean and variance for the data.
xi | 6 | 10 | 14 | 18 | 24 | 28 | 30 |
fi | 2 | 4 | 7 | 12 | 8 | 4 | 3 |
The mean and standard deviation of six observations are 8 and 4, respectively. If each observation is multiplied by 3, find the new mean and new standard deviation of the resulting observations
The mean and standard deviation of 20 observations are found to be 10 and 2, respectively. On rechecking, it was found that an observation 8 was incorrect. Calculate the correct mean and standard deviation in each of the following cases:
- If wrong item is omitted.
- If it is replaced by 12.
The mean and standard deviation of marks obtained by 50 students of a class in three subjects, Mathematics, Physics and Chemistry are given below:
Subject |
Mathematics |
Physics |
Chemistry |
Mean |
42 |
32 |
40.9 |
Standard deviation |
12 |
15 |
20 |
Which of the three subjects shows the highest variability in marks and which shows the lowest?
For a group of 200 candidates, the mean and standard deviations of scores were found to be 40 and 15 respectively. Later on it was discovered that the scores of 43 and 35 were misread as 34 and 53 respectively. Find the correct mean and standard deviation.
The mean and standard deviation of 100 observations were calculated as 40 and 5.1 respectively by a student who took by mistake 50 instead of 40 for one observation. What are the correct mean and standard deviation?
The mean and standard deviation of 20 observations are found to be 10 and 2 respectively. On rechecking it was found that an observation 8 was incorrect. Calculate the correct mean and standard deviation in each of the following cases:
(i) If wrong item is omitted
(ii) if it is replaced by 12.
The mean and standard deviation of a group of 100 observations were found to be 20 and 3 respectively. Later on it was found that three observations were incorrect, which were recorded as 21, 21 and 18. Find the mean and standard deviation if the incorrect observations were omitted.
Show that the two formulae for the standard deviation of ungrouped data
\[\sigma = \sqrt{\frac{1}{n} \sum \left( x_i - X \right)^2_{}}\] and
\[\sigma' = \sqrt{\frac{1}{n} \sum x_i^2 - X^2_{}}\] are equivalent, where \[X = \frac{1}{n}\sum_{} x_i\]
Find the standard deviation for the following distribution:
x : | 4.5 | 14.5 | 24.5 | 34.5 | 44.5 | 54.5 | 64.5 |
f : | 1 | 5 | 12 | 22 | 17 | 9 | 4 |
Calculate the mean and S.D. for the following data:
Expenditure in Rs: | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Frequency: | 14 | 13 | 27 | 21 | 15 |
A student obtained the mean and standard deviation of 100 observations as 40 and 5.1 respectively. It was later found that one observation was wrongly copied as 50, the correct figure being 40. Find the correct mean and S.D.
Calculate the mean, median and standard deviation of the following distribution:
Class-interval: | 31-35 | 36-40 | 41-45 | 46-50 | 51-55 | 56-60 | 61-65 | 66-70 |
Frequency: | 2 | 3 | 8 | 12 | 16 | 5 | 2 | 3 |
Find the mean and variance of frequency distribution given below:
xi: | 1 ≤ x < 3 | 3 ≤ x < 5 | 5 ≤ x < 7 | 7 ≤ x < 10 |
fi: | 6 | 4 | 5 | 1 |
The weight of coffee in 70 jars is shown in the following table:
Weight (in grams): | 200–201 | 201–202 | 202–203 | 203–204 | 204–205 | 205–206 |
Frequency: | 13 | 27 | 18 | 10 | 1 | 1 |
Determine the variance and standard deviation of the above distribution.
Mean and standard deviation of 100 observations were found to be 40 and 10 respectively. If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 respectively, find the correct standard deviation.
The mean and standard deviation of marks obtained by 50 students of a class in three subjects, mathematics, physics and chemistry are given below:
Subject | Mathematics | Physics | Chemistry |
Mean | 42 | 32 | 40.9 |
Standard Deviation | 12 | 15 | 20 |
Which of the three subjects shows the highest variability in marks and which shows the lowest?
Find the coefficient of variation for the following data:
Size (in cms): | 10-15 | 15-20 | 20-25 | 25-30 | 30-35 | 35-40 |
No. of items: | 2 | 8 | 20 | 35 | 20 | 15 |
If the sum of the squares of deviations for 10 observations taken from their mean is 2.5, then write the value of standard deviation.
In a series of 20 observations, 10 observations are each equal to k and each of the remaining half is equal to − k. If the standard deviation of the observations is 2, then write the value of k.
If v is the variance and σ is the standard deviation, then
The standard deviation of the data:
x: | 1 | a | a2 | .... | an |
f: | nC0 | nC1 | nC2 | .... | nCn |
is
If the S.D. of a set of observations is 8 and if each observation is divided by −2, the S.D. of the new set of observations will be
The standard deviation of first 10 natural numbers is
Let x1, x2, ..., xn be n observations. Let \[y_i = a x_i + b\] for i = 1, 2, 3, ..., n, where a and b are constants. If the mean of \[x_i 's\] is 48 and their standard deviation is 12, the mean of \[y_i 's\] is 55 and standard deviation of \[y_i 's\] is 15, the values of a and b are
Show that the two formulae for the standard deviation of ungrouped data.
`sigma = sqrt((x_i - barx)^2/n)` and `sigma`' = `sqrt((x^2_i)/n - barx^2)` are equivalent.
Life of bulbs produced by two factories A and B are given below:
Length of life (in hours) |
Factory A (Number of bulbs) |
Factory B (Number of bulbs) |
550 – 650 | 10 | 8 |
650 – 750 | 22 | 60 |
750 – 850 | 52 | 24 |
850 – 950 | 20 | 16 |
950 – 1050 | 16 | 12 |
120 | 120 |
The bulbs of which factory are more consistent from the point of view of length of life?
Two sets each of 20 observations, have the same standard derivation 5. The first set has a mean 17 and the second a mean 22. Determine the standard deviation of the set obtained by combining the given two sets.
Coefficient of variation of two distributions are 50 and 60, and their arithmetic means are 30 and 25 respectively. Difference of their standard deviation is ______.
If the variance of a data is 121, then the standard deviation of the data is ______.
The standard deviation of a data is ______ of any change in orgin, but is ______ on the change of scale.
The standard deviation is ______to the mean deviation taken from the arithmetic mean.