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Compare the rates of emission of heat by a blackbody maintained at 727°C and at 227°C, if the black bodies are surrounded by an enclosure (black) at 27°C. What would be the ratio of their rate - Physics

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प्रश्न

Compare the rates of emission of heat by a blackbody maintained at 727°C and at 227°C, if the black bodies are surrounded by an enclosure (black) at 27°C. What would be the ratio of their rates of loss of heat?

योग

उत्तर

Data: T1 = 273 + 727 = 1000 K,

T2 = 273 + 227 = 500 K,

T0 = 273 + 27 = 300 K

(i) The rate of emission of heat, `"dQ"/"dt" = sigma"AT"^4`.

We assume that the surface area A is the same for the two bodies.

`∴ ("dQ"//"dt")_1/("dQ"//"dt")_2 = "T"_1^4/"T"_2^4 = ("T"_1/"T"_2)^4`

`= (1000/500)^4 = 2^4 = 16`

(ii) The rate of loss of heat, `"dQ'"/"dt" = sigma"A" ("T"^4 - "T"_0^4)`

`∴ ("dQ'"//"dt")_1/("dQ'"//"dt")_2 = ("T"_1^4 - "T"_0^4)/("T"_2^4 - "T"_0^4)`

`= (10^12 - 81 xx 10^8)/(625 xx 10^8 - 81 xx 10^8)`

`= ((10000 - 81) xx 10^8)/(544 xx 10^8)`

`= 9919/544 = 18.23`

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Interpretation of Temperature in Kinetic Theory
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अध्याय 3: Kinetic Theory of Gases and Radiation - Exercises [पृष्ठ ७४]

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बालभारती Physics [English] 12 Standard HSC Maharashtra State Board
अध्याय 3 Kinetic Theory of Gases and Radiation
Exercises | Q 22 | पृष्ठ ७४

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