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प्रश्न
Differentiate the following w.r.t.x :
y = `x^(4/3) + "e"^x - sinx`
उत्तर
y = `x^(4/3) + "e"^x - sinx`
Differentiating w.r.t. x, we get
`("d"y)/("d"x) = "d"/("d"x)(x^(4/3) + "e"^x - sinx)`
∴ `("d"y)/("d"x) = "d"/("d"x) (x^(4/3)) + "d"/("d"x)("e"^x) - "d"/("d"x)(sinx)`
= `4/3x^(4/3 - 1) + "e"^x - cos x`
= `4/3 x^(1/3) + "e"^x - cos x`
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