Advertisements
Advertisements
प्रश्न
Evaluate:
`2 tan57^circ/(cot33^circ) - cot70^circ/(tan20^circ) - sqrt(2) cos45^circ`
उत्तर
`2 tan57^circ/(cot33^circ) - cot70^circ/(tan20^circ) - sqrt(2) cos45^circ`
`2 tan(90^circ - 33^circ)/(cot33^circ) - cot(90^circ - 20^circ)/(tan20^circ) - sqrt(2)(1/sqrt2)`
`2 cot33^circ/(cot33^circ) - tan20^circ/(tan20^circ) - 1`
= 2 – 1 – 1
= 0
APPEARS IN
संबंधित प्रश्न
What is the value of (cos2 67° – sin2 23°)?
if `3 cos theta = 1`, find the value of `(6 sin^2 theta + tan^2 theta)/(4 cos theta)`
Express the following in terms of angles between 0° and 45°:
cosec68° + cot72°
Use tables to find cosine of 2° 4’
Find A, if 0° ≤ A ≤ 90° and sin 3A – 1 = 0
If tanθ = 2, find the values of other trigonometric ratios.
If A, B and C are interior angles of a triangle ABC, then \[\sin \left( \frac{B + C}{2} \right) =\]
Evaluate: cos2 25° - sin2 65° - tan2 45°
In the given figure, if AB = 14 cm, BD = 10 cm and DC = 8 cm, then the value of tan B is ______.
If y sin 45° cos 45° = tan2 45° – cos2 30°, then y = ______.