Advertisements
Advertisements
प्रश्न
Evaluate `int tan^8 x sec^4 x"d"x`
उत्तर
I = `int tan^8 x sec^4 x"d"x`
= `int tan^8 x(sec^2x)sec^2 x"d"x`
= `int tan^8x(tan^2 x + 1)sec^2 x"d"x`
= `int tan^10 xsec^2x "d"x + int tan^8x sec^2 x"d"x`
= `(tan^11x)/11 + (tan^9x)/9 + "C"`.
APPEARS IN
संबंधित प्रश्न
Evaluate : `intsin(x-a)/sin(x+a)dx`
Find the integrals of the function:
sin2 (2x + 5)
Find the integrals of the function:
sin3 (2x + 1)
Find the integrals of the function:
`cos x/(1 + cos x)`
Find the integrals of the function:
sin4 x
Find the integrals of the function:
cos4 2x
Find the integrals of the function:
`(cos 2x - cos 2 alpha)/(cos x - cos alpha)`
Find the integrals of the function:
`(cos x - sinx)/(1+sin 2x)`
Find the integrals of the function:
`(cos 2x)/(cos x + sin x)^2`
Find `int dx/(x^2 + 4x + 8)`
Evaluate `int_0^pi (x sin x)/(1 + cos^2 x) dx`
Evaluate `int_0^(3/2) |x sin pix|dx`
Find `int_ (sin "x" - cos "x" )/sqrt(1 + sin 2"x") d"x", 0 < "x" < π / 2 `
Find `int_ sin ("x" - a)/(sin ("x" + a )) d"x"`
Find `int_ (log "x")^2 d"x"`
Find `int_ (sin2"x")/((sin^2 "x"+1)(sin^2"x"+3))d"x"`
Find: `int_ (cos"x")/((1 + sin "x") (2+ sin"x")) "dx"`
Find `int "dx"/(2sin^2x + 5cos^2x)`
`int (sin^6x)/(cos^8x) "d"x` = ______.
Evaluate the following:
`int tan^2x sec^4 x"d"x`
Evaluate the following:
`int (sinx + cosx)/sqrt(1 + sin 2x) "d"x`
Evaluate the following:
`int sqrt(1 + sinx)"d"x`
`int (x + sinx)/(1 + cosx) "d"x` is equal to ______.
`int sinx/(3 + 4cos^2x) "d"x` = ______.
The value of the integral `int_(1/3)^1 (x - x^3)^(1/3)/x^4 dx` is
`int (cos^2x)/(sin x + cos x)^2 dx` is equal to