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प्रश्न
Express each one of the following in terms of trigonometric ratios of angles lying between 0° and 45°
sec 76° + cosec 52°
उत्तर
We know that `sec(90^@ - theta) = cosec theta` and `cosec (90^@) = sin theta` So
`sec 76^@ + cosec 52^@ = sec(90^@ - 14^@) + cosec (90^@ - 38^@)`
`= cosec14^@ + sec 38^@`
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