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प्रश्न
Without using tables, evaluate the following: 4(sin430° + cos460°) - 3(cos245° - sin290°).
उत्तर
4(sin430° + cos460°) - 3(cos245° - sin290°).
sin30° = `(1)/(2)`
sin90° = 1
cos45° = `(1)/sqrt(2)`
cos60° = `(1)/(2)`
4(sin430° + cos460°) - 3(cos245° - sin290°)
= `4((1/2)^4 + (1/2)^4) -3((1/sqrt(2))^2 - (1)^2)`
= `4(1/16 + 1/16) -3(1/2 - 1)`
= `4 xx (2)/(16) + 3 xx (1)/(2)`
= `(1)/(2) + (3)/(2)`
= `(4)/(2)`
= 2.
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