Advertisements
Advertisements
प्रश्न
find the value of :
`( tan 45°)/ (cos ec30°) +( sec60°)/(co 45°) – (5 sin 90°)/ (2 cos 0°)`
उत्तर
`( tan 45°)/ (cos ec30°) +( sec60°)/(co 45°) – (5 sin 90°)/ (2 cos 0°) = (1)/(2) + (2)/(1)+(5)/(2)`
`= ( 1 + 4 – 5)/(2) = 0`
APPEARS IN
संबंधित प्रश्न
If A, B and C are interior angles of a triangle ABC, then show that `\sin( \frac{B+C}{2} )=\cos \frac{A}{2}`
Show that:
(i) `2(cos^2 45º + tan^2 60º) – 6(sin^2 45º – tan^2 30º) = 6`
(ii) `2(cos^4 60º + sin^4 30º) – (tan^2 60º + cot^2 45º) + 3 sec^2 30º = 1/4`
Using the formula, sin(A – B) = sinA cosB – cosA sinB, find the value of sin 15º
Evaluate the following :
`((sin 49^@)/(cos 41^@))^2 + (cos 41^@/(sin 49^@))^2`
Evaluate the following :
`((sin 27^@)/(cos 63^@))^2 - (cos 63^@/sin 27^@)^2`
Prove the following :
`(cos(90°−A) sin(90°−A))/tan(90°−A) - sin^2 A = 0`
Prove the following
sin (50° − θ) − cos (40° − θ) + tan 1° tan 10° tan 20° tan 70° tan 80° tan 89° = 1
Evaluate tan 35° tan 40° tan 50° tan 55°
Evaluate: tan 7° tan 23° tan 60° tan 67° tan 83°
Evaluate: `sin 18^@/cos 72^@ + sqrt3 [tan 10° tan 30° tan 40° tan 50° tan 80°]`
Evaluate: `cos 58^@/sin 32^@ + sin 22^@/cos 68^@ - (cos 38^@ cosec 52^@)/(tan 18^@ tan 35^@ tan 60^@ tan 72^@ tan 65^@)`
Find the value of:
tan2 30° + tan2 45° + tan2 60°
If A =30o, then prove that :
sin 2A = 2sin A cos A = `(2 tan"A")/(1 + tan^2"A")`
find the value of: tan 30° tan 60°
Prove that:
cos2 30° - sin2 30° = cos 60°
Prove that:
4 (sin4 30° + cos4 60°) -3 (cos2 45° - sin2 90°) = 2
If sec A = cosec A and 0° ∠A ∠90°, state the value of A
Given A = 60° and B = 30°,
prove that : cos (A - B) = cos A cos B + sin A sin B
If A = 30°;
show that:
(sinA - cosA)2 = 1 - sin2A
If A = 30°;
show that:
4 cos A cos (60° - A). cos (60° + A) = cos 3A
Prove that : sec245° - tan245° = 1
If A = 30° and B = 60°, verify that: `(sin("A" + "B"))/(cos"A" . cos"B")` = tanA + tanB
In ΔABC right angled at B, ∠A = ∠C. Find the value of:
(i) sinA cosC + cosA sinC
(ii) sinA sinB + cosA cosB
If tan `"A" = (1)/(2), tan "B" = (1)/(3) and tan("A" + "B") = (tan"A" + tan"B")/(1 - tan"A" tan"B")`, find A + B.
Find the value of the following:
`(tan45^circ)/("cosec"30^circ) + (sec60^circ)/(cot45^circ) - (5sin90^circ)/(2cos0^circ)`
If 2 sin 2θ = `sqrt(3)` then the value of θ is
If sin α = `1/2`, then find the value of (3 cos α – 4 cos3 α).
Find the value of x if `2 "cosec"^2 30 + x sin^2 60 - 3/4 tan^2 30` = 10
Evaluate: `(5cos^2 60° + 4sec^2 30° - tan^2 45°)/(sin^2 30° + sin^2 60°)`
