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प्रश्न
Prove the following :
`(cos(90°−A) sin(90°−A))/tan(90°−A) - sin^2 A = 0`
उत्तर
We have to prove `(cos(90°−A) sin(90°−A))/tan(90°−A) - sin^2 A = 0`
Left hand side
`= (cos (90^@ - A). sin(90^@ - A))/(tan (90^@ - A))`
`= (sinA.cosA)/cot A = sin^2 A``
`= (sin A.cos A.sin A)/cos A`
`= sin ^2 A`
= Right hand side
Proved
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