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प्रश्न
Verify the following equalities:
sin2 60° + cos2 60° = 1
उत्तर
sin 60° = `sqrt(3)/2`, cos 60° = `1/2`
L.H.S = sin2 60° + cos2 60°
= `(sqrt(3)/2)^2 + (1/2)^2`
= `3/4 + 1/4`
= `4/4`
= 1
L.H.S = R.H.S
Hence it is proved.
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