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प्रश्न
Find the value of x if `2 "cosec"^2 30 + x sin^2 60 - 3/4 tan^2 30` = 10
उत्तर
`2 "cosec"^2 30 + x sin^2 60 - 3/4 tan^2 30` = 10
`\implies 2(2)^2 + x(sqrt(3)/2)^2 - 3/4(1/sqrt(3))^2` = 10
`\implies 2(4) + x(3/4) - 3/4(1/3)` = 10
`\implies 8 + x(3/4) - 1/4` = 10
`\implies` 32 + x(3) – 1 = 40
`\implies` 3x = 9
`\implies` x = 3
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