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प्रश्न
find the value of: sin2 30° + cos2 30°+ cot2 45°
उत्तर
sin2 30° + cos230° + cot2 45° = `(1/2)^2 + (sqrt3/2)^2 + 1^2`
= `(1)/(4) + (3)/(4) + 1`
= 2
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