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Find the equations of the lines, which cut-off intercepts on the axes whose sum and product are 1 and –6, respectively. - Mathematics

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प्रश्न

Find the equations of the lines, which cut-off intercepts on the axes whose sum and product are 1 and –6, respectively.

योग

उत्तर

Let the segments cut on the axes be a and b.

Given: a + b = 1, ab = –6

b = 1 – a

∴ a(1 – a) = –6

or a – a2 = –6

a2 – a – 6 = 0

or (a – 3) (a + 2) = 0

∴ a = 3, –2

∴ b = –2, 3

3, equation of line with –2 intercept,

`"x"/3 + "y"/(-2) = 1`

or 2x – 3y = 6

And equation of line with -2, 3 intercepts,

`"x"/(-2) + "y"/3 = 1`

or –3x + 2y = 6

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अध्याय 10: Straight Lines - Miscellaneous Exercise [पृष्ठ २३३]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 10 Straight Lines
Miscellaneous Exercise | Q 3 | पृष्ठ २३३

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