Advertisements
Advertisements
प्रश्न
If θ = 30°, verify that: sin 3θ = 4sinθ . sin(60° - θ) sin(60° + θ)
उत्तर
Given: θ = 30°
sin3θ
= sin3 x 30°
= sin90°
= 1
4sinθ . sin(60° - θ) sin(60° + θ)
= 4sin 30° x sin(60° - 30°) x sin(60° + 30°)
= 4sin30° x sin30° x sin90°
= `4 xx (1)/(2) xx (1)/(2) xx 1`
= 1
⇒ sin3θ = 4sinθ . sin(60° - θ)sin(60° + θ).
APPEARS IN
संबंधित प्रश्न
Solve the following equation for A, if 2 sin 3 A = 1
If A = B = 60°, verify that: tan(A - B) = `(tan"A" - tan"B")/(1 + tan"A" tan"B"")`
In a right triangle ABC, right angled at C, if ∠B = 60° and AB = 15units, find the remaining angles and sides.
Find the value of 'x' in each of the following:
In the given figure; ∠B = 90°, ∠ADB = 30°, ∠ACB = 45° and AB = 24 m. Find the length of CD.
Evaluate the following: `(sec32° cot26°)/(tan64° "cosec"58°)`
Evaluate the following: sin28° sec62° + tan49° tan41°
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cosec64° + sec70°
Evaluate the following: sin35° sin45° sec55° sec45°
Evaluate the following: `(2sin25° sin35° sec55° sec65°)/(5tan 29° tan45° tan61°) + (3cos20° cos50° cot70° cot40°)/(5tan20° tan50° sin70° sin40°)`
