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If Sec2a = Cosec(A - 42°), Where 2a is an Acute Angle, Then Find the Value of A. - Mathematics

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प्रश्न

If sec2A = cosec(A - 42°), where 2A is an acute angle, then find the value of A.  

योग

उत्तर

\[\sec2A = cosec\left( A - 42^\circ \right)\]

\[ \Rightarrow cosec\left( 90^\circ- 2A \right) = cosec\left( A - 42^\circ \right)\]

Comparing both sides, we get

\[90^\circ- 2A = A - 42^\circ\]

\[ \Rightarrow 2A + A = 90^\circ + 42^\circ\]

\[ \Rightarrow 3A = 132^\circ\]

\[ \Rightarrow A = \frac{132^\circ}{3}\]

\[ \therefore A = 44^\circ\]

Hence, the value of A is 44° 

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अध्याय 7: Trigonometric Ratios of Complementary Angles - Exercises [पृष्ठ ३१४]

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आरएस अग्रवाल Mathematics [English] Class 10
अध्याय 7 Trigonometric Ratios of Complementary Angles
Exercises | Q 11 | पृष्ठ ३१४

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