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If y = 5 cos x – 3 sin x, prove that d2ydx2+y=0 - Mathematics

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प्रश्न

If y = 5 cos x – 3 sin x, prove that `(d^2y)/(dx^2) + y = 0`

योग

उत्तर

Given, y = 5 cos x - 3 sin x

Differentiating both sides with respect to x,

`dy/dx = 5  d/dx cos x - 3  d/dx  sin x`

= 5 (- sin x) - 3 cos x = - 5 sin x - 3 cos x

Differentiating both sides again with respect to x,

`(d^2 y)/dx= - 5  d/dx  sin x - 3  d/dx  cos x`

= - 5 cos x - 3 (- sin x) = 3 sin x - 5 cos x

Hence, `(d^2 y)/dx^2 + y ` = 3 sin x - 5 cos x + 5 cos x - 3 sin x     ...(On substituting the value of y)

= 0

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अध्याय 5: Continuity and Differentiability - Exercise 5.7 [पृष्ठ १८३]

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एनसीईआरटी Mathematics [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.7 | Q 11 | पृष्ठ १८३

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