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प्रश्न
Find the second order derivative of the function.
sin (log x)
उत्तर
Let, y = sin (log x)
Differentiating both sides with respect to x,
`dy/dx = d/dx sin (log x) = cos (log x) d/dx log x`
`= cos (log x) * 1/x = (cos (log x))/x`
`(d^2y)/dx^2 = cos (logx). (-1/x^2) + 1/x. {-sin (log x)} 1/x`
`= (-cos(log x))/x^2 - (sin (log x))/x^2`
`= -1/x^2 [cos (logx) + sin (log x)]`
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