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प्रश्न
In fig., chords AB and CD of a circle intersect at P. AP = 5cm, BP= 3cm and CP = 2.5cm. Determine the length of DP.
उत्तर
Let DP = x cm
In Δ APC and Δ DPB
∠ PAC = ∠ PDB (angles in the some segment)
∠ APC = ∠ DPB (vertically opposite angle)
∴ Δ APC ~ Δ DPB {AA corollary)
`"AP"/"DP" = "PC"/"PB"` (similar sides of similar triangles)
`5/"x" = 2.5/3`
`=> "x" = 15/2.5 = 150/25` = 6 cm
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