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प्रश्न
In the following figure, ray PT is the bisector of ∠QPR Find the value of x and perimeter of ∠QPR.
उत्तर
In Δ PQR, PT is the bisector of ∠P
∴ `"QT"/"TR" = "PQ"/"PR"`
⇒ `4/5 = 3.6/"PR"`
⇒ 4PR = 18
⇒PR = `18/4= 9/2 = 4.5`cm
⇒ QR =QT +TR
⇒ QR = 4+5 = 9 cm
⇒ Perimeter of Δ PQR =PQ+QR +PR
⇒ 3.6+9+4.5 = 17.1 cm
⇒ Perimeter of Δ PQR = 17.1 cm
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