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प्रश्न
\[\lim_{x \to 1} \frac{x^2 + 1}{x + 1}\]
उत्तर
\[\lim_{x \to 1} \left( \frac{x^2 + 1}{x + 1} \right)\]
\[ = \frac{1^2 + 1}{1 + 1}\]
\[ = 1\]
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