Advertisements
Advertisements
प्रश्न
Solve for x : 2 cos 3x - 1 = 0
उत्तर
2 cos 3x – 1 = 0
cos 3x = `(1)/(2)`
3x = 60°
x = 20°
APPEARS IN
संबंधित प्रश्न
If sin x + cos y = 1 and x = 30°, find the value of y
Solve for x : sin (x + 10°) = `(1)/(2)`
If `sqrt(2) = 1.414 and sqrt(3) = 1.732`, find the value of the following correct to two decimal places tan60°
If θ < 90°, find the value of: `tan^2θ - (1)/cos^2θ`
Find the value of: `sqrt((1 - sin^2 60°)/(1 + sin^2 60°)` If 3 tan2θ - 1 = 0, find the value
a. cosθ
b. sinθ
If ΔABC is a right triangle such that ∠C = 90°, ∠A = 45° and BC =7units, find ∠B, AB and AC.
Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.
Find x and y, in each of the following figure:
If sin(θ - 15°) = cos(θ - 25°), find the value of θ if (θ-15°) and (θ - 25°) are acute angles.
If P, Q and R are the interior angles of ΔPQR, prove that `cot(("Q" + "R")/2) = tan "P"/(2)`