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The Following Graph Shows the Variation of Photocurrent for a Photosensitive Metal - Physics

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प्रश्न

The following graph shows the variation of photocurrent for a photosensitive metal : 


(a) Identify the variable X on the horizontal axis.

(b) What does the point A on the horizontal axis represent?

(c) Draw this graph for three different values of frequencies of incident radiation v1, v2 and v3 (v1 > v2 > v3) for same intensity.

(d) Draw this graph for three different values of intensities of incident radiation I1, I2 and I3 (I1 > I2 > I3) having same frequency.

उत्तर

(a) Variable X is the accelerating potential applied across the photosensitive material.

(b) A represents the stopping potential for the given photosensitive metal. Stopping potential is the minimum negative potential V0 applied across the photosensitive material at which the photoelectric current becomes zero.

(c) Graph for three different values of frequencies of incident radiation v1, v2 and v3 (v1 > v2 > v3) for same intensity

(d) Graph for three different values of intensities of incident radiation I1, I2 and I3 (I1 > I2 > I3) having same frequency

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Experimental Study of Photoelectric Effect
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2016-2017 (March) All India Set 3

संबंधित प्रश्न

The work function for the following metals is given: 

Na: 2.75 eV; K: 2.30 eV; Mo: 4.17 eV; Ni: 5.15 eV

Which of these metals will not give photoelectric emission for a radiation of wavelength 3300 Å from a He-Cd laser placed 1 m away from the photocell? What happens if the laser is brought nearer and placed 50 cm away?


The work function of a metal is hv0. Light of frequency v falls on this metal. Photoelectric effect will take place only if


Light of wavelength λ falls on a metal with work-function hc/λ0. Photoelectric effect will take place only if


When the sun is directly overhead, the surface of the earth receives 1.4 × 103 W m−2 of sunlight. Assume that the light is monochromatic with average wavelength 500 nm and that no light is absorbed in between the sun and the earth's surface. The distance between the sun and the earth is 1.5 × 1011 m. (a) Calculate the number of photons falling per second on each square metre of earth's surface directly below the sun. (b) How many photons are there in each cubic metre near the earth's surface at any instant? (c) How many photons does the sun emit per second?

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


A sphere of radius 1.00 cm is placed in the path of a parallel beam of light of large aperture. The intensity of the light is 0.5 W cm−2. If the sphere completely absorbs the radiation falling on it, find the force exerted by the light beam on the sphere.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


The electric field associated with a monochromatic beam is 1.2 × 1015 times per second. Find the maximum kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0 eV.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


In photoelectric effect the photo current ______.


Consider a thin target (10–2 cm square, 10–3 m thickness) of sodium, which produces a photocurrent of 100 µA when a light of intensity 100W/m2 (λ = 660 nm) falls on it. Find the probability that a photoelectron is produced when a photons strikes a sodium atom. [Take density of Na = 0.97 kg/m3].


How would the stopping potential for a given photosensitive surface change if the intensity of incident radiation was decreased? Justify your answer.


  • Assertion (A): For the radiation of a frequency greater than the threshold frequency, the photoelectric current is proportional to the intensity of the radiation.
  • Reason (R): Greater the number of energy quanta available, the greater the number of electrons absorbing the energy quanta and the greater the number of electrons coming out of the metal.

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