मराठी

∆Abc is Such that Ab = 3 Cm, Bc = 2 Cm and Ca = 2.5 Cm. If ∆Def ∼ ∆Abc and Ef = 4 Cm, Then Perimeter of ∆Def is (A) 7.5 Cm (B) 15 Cm (C) 22.5 Cm (D) 30 Cm - Mathematics

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प्रश्न

∆ABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. If ∆DEF ∼ ∆ABC and EF = 4 cm, then perimeter of ∆DEF is

पर्याय

  • 7.5 cm

  • 15 cm

  • 22.5 cm

  • 30 cm

MCQ

उत्तर

Given: In ΔABC, AB = 3cm, BC = 2cm, CA = 2.5cm. `ΔDEF ∼ Δ ABC ` and EF = 4cm.

To find: Perimeter of ΔDEF.

We know that if two triangles are similar, then their sides are proportional

Since ΔABC and ΔDEF are similar,

`(AB)/(DE)=(BC)/(EF)=(CA)/(FD)`

`3/(DE)=2/4=2.5/(FD)`

`3/(DE)=2/4`...............(1)

`DE=6cm`

`2/4=2.5/(FD)`

`FD=5cm......................(2)

From (1) and (2), we get

Perimeter of ΔDEF =  DE + EF + FD = 6 + 4 +5 = 15 cm

Hence the correct answer is `b`

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पाठ 7: Triangles - Exercise 7.10 [पृष्ठ १३५]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 7 Triangles
Exercise 7.10 | Q 40 | पृष्ठ १३५

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