Advertisements
Advertisements
प्रश्न
Arrange the sides of the following triangles in an ascending order:
ΔDEF, ∠D = 38°, ∠E = 58°.
उत्तर
In ΔDEF,
∠D + ∠E + ∠F = 180°
38° + 58° + ∠F = 180°
96° + ∠F = 180°
∠F = 180° - 96°
∠F = 84°
Hence, ∠D = 38°, ∠E = 58°, ∠F = 84°
38° < 58° < 84°
Hence, ascending order of the angles in the
given triangle is ∠D < ∠E < ∠F.
Hence, ascending order of sides in triangle
EF, DF, DE.
APPEARS IN
संबंधित प्रश्न
In a huge park people are concentrated at three points (see the given figure):
A: where there are different slides and swings for children,
B: near which a man-made lake is situated,
C: which is near to a large parking and exit.
Where should an ice-cream parlour be set up so that maximum number of persons can approach it?
(Hint: The parlor should be equidistant from A, B and C)
In the following figure ; AC = CD; ∠BAD = 110o and ∠ACB = 74o.
Prove that: BC > CD.
Name the greatest and the smallest sides in the following triangles:
ΔDEF, ∠D = 32°, ∠E = 56° and ∠F = 92°.
Arrange the sides of the following triangles in an ascending order:
ΔABC, ∠A = 45°, ∠B = 65°.
In ΔABC, the exterior ∠PBC > exterior ∠QCB. Prove that AB > AC.
Prove that the perimeter of a triangle is greater than the sum of its three medians.
D is a point on the side of the BC of ΔABC. Prove that the perimeter of ΔABC is greater than twice of AD.
In ΔPQR, PS ⊥ QR ; prove that: PQ > QS and PQ > PS
In ΔPQR, PS ⊥ QR ; prove that: PQ > QS and PR > PS
In ΔABC, D is a point in the interior of the triangle. Prove that DB + DC < AB + AC.