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प्रश्न
Determine the distance between the pair of parallel lines:
4x − 3y − 9 = 0 and 4x − 3y − 24 = 0
उत्तर
The parallel lines are
4x − 3y − 9 = 0 ... (1)
4x − 3y − 24 = 0 ... (2)
Let d be the distance between the given lines.
\[\Rightarrow d = \left| \frac{- 9 + 24}{\sqrt{4^2 + \left( - 3 \right)^2}} \right| = \frac{15}{5} = 3\] units
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