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Differentiate the following w.r.t.x: x2+4x-7 - Mathematics and Statistics

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प्रश्न

Differentiate the following w.r.t.x: `sqrt(x^2 + 4x - 7)`

बेरीज

उत्तर

y = `sqrt(x^2 + 4x - 7) [sqrt(x) = 1/(2sqrtx)]`

Differentiating w.r.t. x, we get

`"dy"/"dx" = (1)/(2sqrt(x^2 + 4x - 7)). "d"/"dx"(x^2 + 4x - 7)`

`= (1)/(2sqrt(x^2 + 4x - 7)).("d"/"dx"x^2 + "d"/"dx"4x - "d"/"dx"7)`

= `(1)/(2sqrt(x^2 + 4x - 7)).(2x + 4 - 0)`

= `(2(x + 2))/(2sqrt(x^2 + 4x - 7)`

= `((x + 2))/(sqrt(x^2 + 4x - 7)`

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Differentiation
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Differentiation - Exercise 1.1 [पृष्ठ ११]

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