मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Discuss Continuity of F(X) = X 3 − 64 √ X 2 + 9 − 5 for X≠4 = 10 for X = 4 at X = 4 - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Discuss continuity of f(x) =`(x^3-64)/(sqrt(x^2+9)-5)` For x ≠ 4 

= 10 for x = 4  at x = 4

बेरीज

उत्तर

`f(4) = 10`

`lim_(x→4)f(x)=lim_(x→4)(x^3-64)/(sqrt(x^2+9)-5)`


`=lim_(x→4)(x^3-64)/(sqrt(x^2+9)-5)`


`lim_(x→4)(x^3-4^3)/(sqrt(x^2+9)-5)xx(sqrt(x^2+9)+5)/(sqrt(x^2+9)+5)`


`Lim_(x→4)((x^3-4^3)(sqrtx^2+9+5))/((sqrtx^2+9)^2-(-5)^2)`


`Lim_(x→4) ((x-4)(x^2+4x+16)(sqrt(x^2+9)+5))/(x^2+9-25)`    .......`[a^3 – b^3 = (a – b) (a^2 + ab + b^2))`


`Lim_(x→4) ((x-4)(x^2+4x+16)(sqrt(x^2+9)+5))/(x^2-16)`


`Lim_(x→4) ((x-4)(x^2+4x+16)(sqrt(x^2+9)+5))/((x-4)(x+4)`)


`Lim_(x→4) ((x^2+4x+16)(sqrt(x^2+9)+5))/(x+4)`


`(((4)^2+4(4)+16)(sqrt(4^2+9)+5))/(4+4)`


`((16+16+16)(sqrt(16+9)+5))/8`


`((16+16+16)(sqrt(25)+5))/8`


`((16+16+16)(5+5))/8`


`(48x10)/8`

`f(x)lim_(x→4)=60`

`lim_(x→4) f(x)≠f(4)` 

∴ f (x) is not continuous at x = 4.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2017-2018 (March)

APPEARS IN

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Examine the following function for continuity:

f (x) = x – 5


Determine the values of a, b, c for which the function f(x) = `{((sin(a + 1)x + sin x)/x, "for"   x < 0),(x, "for"  x = 0),((sqrt(x + bx^2) - sqrtx)/(bx^(3"/"2)), "for"  x > 0):}` is continuous at x = 0.


For what value of k is the following function continuous at x = 2? 

\[f\left( x \right) = \begin{cases}2x + 1 ; & \text{ if } x < 2 \\ k ; & x = 2 \\ 3x - 1 ; & x > 2\end{cases}\]

Find the values of a and b so that the function f(x) defined by \[f\left( x \right) = \begin{cases}x + a\sqrt{2}\sin x , & \text{ if }0 \leq x < \pi/4 \\ 2x \cot x + b , & \text{ if } \pi/4 \leq x < \pi/2 \\ a \cos 2x - b \sin x, & \text{ if }  \pi/2 \leq x \leq \pi\end{cases}\]becomes continuous on [0, π].


If \[f\left( x \right) = \begin{cases}\frac{x^2 - 16}{x - 4}, & \text{ if }  x \neq 4 \\ k , & \text{ if }  x = 4\end{cases}\]  is continuous at x = 4, find k.


If  \[f\left( x \right) = \begin{cases}\frac{\sin (a + 1) x + \sin x}{x} , & x < 0 \\ c , & x = 0 \\ \frac{\sqrt{x + b x^2} - \sqrt{x}}{bx\sqrt{x}} , & x > 0\end{cases}\]is continuous at x = 0, then 


Let f (x) = |x| and g (x) = |x3|, then


The set of points where the function f (x) = x |x| is differentiable is 

 


Let \[f\left( x \right) = \begin{cases}1 , & x \leq - 1 \\ \left| x \right|, & - 1 < x < 1 \\ 0 , & x \geq 1\end{cases}\] Then, f is 


Examine the continuity of f(x)=`x^2-x+9  "for"  x<=3`

=`4x+3  "for"  x>3,  "at"  x=3` 


`f(x)=(x^2-9)/(x - 3)` is not defined at x = 3. what value should be assigned to f(3) for continuity of f(x) at = 3?


If the function f is continuous at x = 0

Where f(x) = 2`sqrt(x^3 + 1)` + a,  for x < 0,
= `x^3 + a + b,  for x > 0
and f (1) = 2, then find a and b.


The total cost C for producing x units is Rs (x2 + 60x + 50) and the price is Rs (180 - x) per unit. For how many units the profit is maximum.


Discuss the continuity of the function at the point given. If the function is discontinuous, then remove the discontinuity.

f (x) = `(sin^2 5x)/x^2` for x ≠ 0 
= 5   for x = 0, at x = 0


The set of points where the functions f given by f(x) = |x – 3| cosx is differentiable is ______.


f(x) = `{{:(|x|cos  1/x",", "if"  x ≠ 0),(0",", "if"  x = 0):}` at x = 0


f(x) = `{{:(("e"^(1/x))/(1 + "e"^(1/x))",", "if"  x ≠ 0),(0",", "if"  x = 0):}` at x = 0 


f(x) = |x| + |x − 1| at x = 1


Find the values of a and b such that the function f defined by
f(x) = `{{:((x - 4)/(|x - 4|) + "a"",",  "if"  x < 4),("a" + "b"",",  "if"  x = 4),((x - 4)/(|x - 4|) + "b"",", "if"  x > 4):}`
is a continuous function at x = 4.


Write the number of points where f(x) = |x + 2| + |x - 3| is not differentiable.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×