मराठी

Evaluate: (27125)23×(925)32 - Mathematics

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प्रश्न

Evaluate:

(27125)23×(925)-32

बेरीज

उत्तर

(27125)23×(925)-32

= (3×3×35×5×5)23×(3×35×5)-32

= [(35)3]23×[(35)2]-32

= (35)3×23×(35)2×-32

= (35)2×(35)-3

= (35)2-3

= (35)-1

= 135

=53 

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Laws of Exponents
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Indices (Exponents) - Exercise 7 (A) [पृष्ठ ९८]

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सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 7 Indices (Exponents)
Exercise 7 (A) | Q 1.3 | पृष्ठ ९८
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