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प्रश्न
Evaluate: `3(sin72°)/(cos18°) - (sec32°)/("cosec"58°)`.
उत्तर
`3(sin72°)/(cos18°) - (sec32°)/("cosec"58°)`
= `3(sin(90° - 18°))/(cos 18°) - sec(90° - 58°)/("cosec"58°)`
= `3(cos 18°)/(cos 18°) - ("cosec"58°)/("cosec"58°)`
= 3 - 1
= 2
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