Advertisements
Advertisements
प्रश्न
Evaluate:
`(cos75^@)/(sin15^@) + (sin12^@)/(cos78^@) - (cos18^@)/(sin72^@)`
उत्तर
`(cos75^@)/(sin15^@) + (sin12^@)/(cos78^@) - (cos18^@)/(sin72^@)`
= `(cos(90^@ - 15^@))/(sin15^@) + (sin(90^@ - 78^@))/(cos78^@) - (cos(90^@ - 72^@))/(sin72^@)`
= `(sin15^@)/(sin15^@) + (cos78^@)/(cos78^@) - (sin72^@)/(sin72^@)`
= 1 + 1 – 1
= 1
APPEARS IN
संबंधित प्रश्न
If sec 4A = cosec (A− 20°), where 4A is an acute angle, find the value of A.
if `cot theta = sqrt3` find the value of `(cosec^2 theta + cot^2 theta)/(cosec^2 theta - sec^2 theta)`
Evaluate.
`cot54^@/(tan36^@)+tan20^@/(cot70^@)-2`
Evaluate:
`(sin35^circ cos55^circ + cos35^circ sin55^circ)/(cosec^2 10^circ - tan^2 80^circ)`
Use tables to find sine of 21°
If \[\cos \theta = \frac{2}{3}\] find the value of \[\frac{\sec \theta - 1}{\sec \theta + 1}\]
If A + B = 90° and \[\tan A = \frac{3}{4}\]\[\tan A = \frac{3}{4}\] what is cot B?
If \[\frac{160}{3}\] \[\tan \theta = \frac{a}{b}, \text{ then } \frac{a \sin \theta + b \cos \theta}{a \sin \theta - b \cos \theta}\]
If A + B = 90°, then \[\frac{\tan A \tan B + \tan A \cot B}{\sin A \sec B} - \frac{\sin^2 B}{\cos^2 A}\]
Evaluate:
3 cos 80° cosec 10°+ 2 sin 59° sec 31°