Advertisements
Advertisements
प्रश्न
Evaluate the following :
`tan 10^@/cot 80^@`
उत्तर
We are given that `tan 10^@/cot 80^@`
Since `tan (9- theta) = cot theta`
`=> (tan 10)/(cot 80) = (tan(90 - 80))/(cot 80)`
`=> tan 10/cot 80 = cot 80/cot 80`
`=> tan 10/cot 80 = 1`
Therefore `tan 10/cot 80 = 1`
APPEARS IN
संबंधित प्रश्न
Evaluate the following :
`cos 19^@/sin 71^@`
Evaluate the following :
cosec 31° − sec 59°
Express each one of the following in terms of trigonometric ratios of angles lying between
0° and 45°
Sin 59° + cos 56°
Prove that sin 48° sec 42° + cos 48° cosec 42° = 2
Evaluate: tan 7° tan 23° tan 60° tan 67° tan 83°
prove that:
sin (2 × 30°) = `(2 tan 30°)/(1+tan^2 30°)`
If sec A = cosec A and 0° ∠A ∠90°, state the value of A
Without using tables, evaluate the following: tan230° + tan260° + tan245°
If sin(A +B) = 1(A -B) = 1, find A and B.
If tan `"A" = (1)/(2), tan "B" = (1)/(3) and tan("A" + "B") = (tan"A" + tan"B")/(1 - tan"A" tan"B")`, find A + B.