Advertisements
Advertisements
प्रश्न
Evaluate: tan 7° tan 23° tan 60° tan 67° tan 83°
उत्तर
tan 7° tan 23° tan 60° tan (90° - 23) tan (90° - 7°)
⇒ tan 7° tan 23° tan 60° cot 23° tan 60°
`1 xx 1 xx sqrt3 = sqrt3`
APPEARS IN
संबंधित प्रश्न
Evaluate the following :
`(cot 40^@)/cos 35^@ - 1/2 [(cos 35^@)/(sin 55^@)]`
Express each one of the following in terms of trigonometric ratios of angles lying between 0° and 45°
cosec 54° + sin 72°
Evaluate: `sin 18^@/cos 72^@ + sqrt3 [tan 10° tan 30° tan 40° tan 50° tan 80°]`
Prove that:
sin 60° cos 30° + cos 60° . sin 30° = 1
If sin x = cos y; write the relation between x and y, if both the angles x and y are acute.
If A = 30°;
show that:
`(1 – cos 2"A")/(sin 2"A") = tan"A"`
Without using tables, evaluate the following: sin230° sin245° + sin260° sin290°.
Find the value of x in the following: 2 sin3x = `sqrt(3)`
Find the value of x in the following: cos2x = cos60° cos30° + sin60° sin30°
If A = 30° and B = 60°, verify that: `(sin("A" -"B"))/(sin"A" . sin"B")` = cotB - cotA
