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प्रश्न
Express each one of the following in terms of trigonometric ratios of angles lying between 0° and 45°
cosec 54° + sin 72°
उत्तर
We know `sin(90^@ - theta) = cos theta` and `cosec(90^@ - theta) = sec theta` So
`cosec 54° + sin 72° = cosec(90^@ - 36^@) + sin (90^@ - 18^@)`
`= sec 36^@ + cos 18^@`
hus the desired expression is sec 36^@ + cos 18^@`
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