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प्रश्न
Find the angle between two radii at the centre of the circle as shown in the figure. Lines PA and PB are tangents to the circle at other ends of the radii and ∠APR = 110°.
उत्तर
\[ \Rightarrow \angle APB = 70^o\]
Also,
\[\angle\]OAP = \[\angle\]OBP = 90º (Radius is perpendicular to the tangent at the point of contact)
\[ \Rightarrow 70^o + 90^o + \angle BOA + 90^o = 360^o\]
\[ \Rightarrow \angle BOA = 110^o\]
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