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प्रश्न
Find the value of `tan^-1 (- 1/sqrt(3)) + cot^-1(1/sqrt(3)) + tan^-1(sin((-pi)/2))`
उत्तर
We have `tan^-1 (- 1/sqrt(3)) + cot^-1(1/sqrt(3)) + tan^-1(sin((-pi)/2))`
= `tan^-1(tan(- pi/6)) + cot^-1(cot pi/3) + tan^-1(-1)`
= `- pi/6 + pi/3 + (- pi/4)`
= `-pi/12`
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