English

Find the value of tan-1(-13)+cot-1(13)+tan-1(sin(-π2)) - Mathematics

Advertisements
Advertisements

Question

Find the value of `tan^-1 (- 1/sqrt(3)) + cot^-1(1/sqrt(3)) + tan^-1(sin((-pi)/2))`

Sum

Solution

We have `tan^-1 (- 1/sqrt(3)) + cot^-1(1/sqrt(3)) + tan^-1(sin((-pi)/2))`

= `tan^-1(tan(- pi/6)) + cot^-1(cot  pi/3) + tan^-1(-1)`

= `- pi/6 + pi/3 + (- pi/4)`

= `-pi/12`

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Inverse Trigonometric Functions - Exercise [Page 35]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 12
Chapter 2 Inverse Trigonometric Functions
Exercise | Q 4 | Page 35

RELATED QUESTIONS

Write the principal value of `tan^(-1)+cos^(-1)(-1/2)`


Find the principal value of the following:

`sin^-1((sqrt3+1)/(2sqrt2))`


For the principal value, evaluate of the following:

`tan^-1(-1)+cos^-1(-1/sqrt2)`


Find the principal value of the following:

`sec^-1(-sqrt2)`


Find the principal value of the following:

`sec^-1(2tan  (3pi)/4)`


​Find the principal value of the following:

cosec-1(-2)


For the principal value, evaluate the following:

`sin^-1(-sqrt3/2)+\text{cosec}^-1(-2/sqrt3)`


For the principal value, evaluate the following:

`sin^-1[cos{2\text(cosec)^-1(-2)}]`


if sec-1  x = cosec-1  v. show that `1/x^2 + 1/y^2 = 1`


Find the value of `sec(tan^-1  y/2)`


Find the value of `sin(2tan^-1  2/3) + cos(tan^-1 sqrt(3))`


Which of the following corresponds to the principal value branch of tan–1?


The value of sin (2 sin–1 (.6)) is ______.


The value of tan2 (sec–12) + cot2 (cosec–13) is ______.


The domain of the function cos–1(2x – 1) is ______.


If `cos(sin^-1  2/5 + cos^-1x)` = 0, then x is equal to ______.


The set of values of `sec^-1 (1/2)` is ______.


The principal value of `tan^-1 sqrt(3)` is ______.


The value of expression `tan((sin^-1x + cos^-1x)/2)`, when x = `sqrt(3)/2` is ______.


The value of the expression (cos–1x)2 is equal to sec2x.


The domain of trigonometric functions can be restricted to any one of their branch (not necessarily principal value) in order to obtain their inverse functions.


The general solution of the equation `"cot"  theta - "tan"  theta = "sec"  theta` is ____________ where `(n in I).`


`2  "cos"^-1 "x = sin"^-1 (2"x" sqrt(1 - "x"^2))` is true for ____________.


`"cos" ["tan"^-1 {"sin" ("cot"^-1  "x")}]` is equal to ____________.


`"sec" {"tan"^-1 (-"y"/3)}` is equal to ____________.


What is the principle value of `sin^-1 (1/sqrt(2))`?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×